BAR BENDING SCHEDULE

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BAR BENDING SCHEDULE

BAR BENDING SCHEDULE OF BEAM (5.1 x 0.3)



Main steel bar 16 mm ^ Main bent up bar 16 mm ^ Anchor bar 12 mm ^ Stirrups 8 mm ^
1. Length of main steel bar 16mm ^ No. of bar = 2
Length of bar , L = Clear span + bearing
= 4.8 + 0.3 = 5.1 m
Total length of bar = L + 2 hooks (2x9 D) = 5.1 + (18 x 0.016) = 5.088 m
2.  Main bent up bar 16 mm ^
No. of bar = 1
Length of bar = L = Clear span + bearing = 5.1 m
Total length of bar = L + 2 hooks + 0.84 for two- bent up = 5.1 + (18x 0.016) + (0.84x 0.10) = 5.472 m
3.  Anchor bar 12 mm ^
No. of bar = 2 Length of bar = L = 5.1m Total length of bar = L + 2 hooks
= 5.1+ (2(9) x 0.012) = 5.316 m
4.     Stirrups 8 mm ^ @ 180 c/c
L = 5.1 m
No. of stirrups at 5 cm c/c at end = 2 No. No. of stirrups at 18 cm c/c in b/w = 510-10/18 = 28 99 | Page


Total No. of stirrups = 2 + 28= 30
Length of one stirrups = 2(44+ 22) + 30 = 162 cm
= 1.62 m
Schedule of Bars (R.C.C. Beam).
Sr. no.
Description
Shape
Length
No.
Total length (m)
Wt./m length
Total wt. (kg)
1.
Main steel bar 16mm ^

5.39
2
10.78
1.58
17.0
2.
Main bent up bar 16mm ^

5.5
1
5.50
1.58
8.7
3
Anchor bar 12mm ^

5.32
2
10.64
0.89
9.4
4.
Stirrups 8 mm^
*
1.6
30
48
0.4
19.2
Total 54.30 kg


Main steel bar 12 mm ^ Anchor bar 12 mm ^ Stirrups 8 mm ^
1.    Length of main steel bar 12mm ^
No. of bar = 2
Length of bar , L = Clear span + bearing = 2.8 + 0.3 = 3.1 m Total length of bar = L + 2 hooks (2x9 D) = 3.1 + (18 x 0.012) = 3.32 m
2.   Anchor bar 12 mm ^
No. of bar = 2 Length of bar = L = 3.1m Total length of bar = L + 2 hooks
= 3.1+ (2(9) x 0.012) = 3.32 m
3. Stirrups 8 mm ^ @ 180 c/c L = 3.1 m
No. of stirrups at 5 cm c/c at end = 2 No. No. of stirrups at 18 cm c/c in b/w = 300-10/18 = 16 Total No. of stirrups = 2 + 16 = 18 Length of stirrups = 2 (27 cm + 25 cm) + 30 extra 101 | Page

= 134 cm = 1.34 m So total length of 16 nos. stirrups each.
Sr. no.
Description
Shape
Length
No.
Total length (m)
Wt./m length
Total wt. (kg)
1.
Main steel bar12 mm
l

3.32
2
6.64
0.89
5.91
2.
Anchor bar 12mm |

3.32
2
6.64
0.89
5.91
3.
Stirrups 8 mm|
*
1.34
16
21.44
0.4
8.6
Total 20.4 kg

1.      14 mm | bar in base footing
2.       18 mm | bar vertical
3.      6 mm | ties @ 290 mm c/c
1. 11 bar 14 mm |
C/c spacing = 1900/11 = 172 mm
Total No. of bar = 11+ 11 = 22 no. Total length of bar = 1.6 + 2 hooks
= ( 1.6 + ( 18 x 0.014) = 1.85 m
Total bar length = 22x 1.85 = 40.7 m
2. 16 mm 18 ^ vertical bar No. of bar = 4 no. Total length of bar = 3+ 0.4 + 0.20 + 12d +0.20 = 4 m
3. 6 mm ^ tie bar @ 290 C/c
No. of tie = (300+ 40)/2+ 1 = 12.7 4(250) + 24 x 0.08 = = say 13 no.
Length = 4 C + 24 D = 1001.9 mm = 1.01 m
Schedule of Bars (R.C.C. square column)
Sr. no.
Description
Shape
Length
No.
Total length (m)
Wt./m length
Total wt. (kg)
1.
14 mm ^ bar

1.85
22
40.7
1.2
49
2.
18 mm ^ vertical bar


4
4
16
1.58
25.3
3.
6 mm ^ tie @ 29 cm c/c

> 
1.01
13
13.13
0.22
2.9


1. Main bar of 10 mm ^ @ 190 mm c/c L = Length - 2 cover = 12.6 - 2x 0.04 = 12.52 m Total length of main bar = 12.52 + 2 hooks = 12.52 + ( 18x 0.010) = 12.7 m
No. of bar = (51.1/.38) + 1 = (51100/ 380) + 1 = 135.4 no. say 136 no.
2. Bent -up bar of 10 mm ^ @ 190 mm c/c
= 12.6 + bearing - 2 cover + 2 bent-up + 2 hooks

= 12.6 + 0.20 - (2x 0.04) + ( 2 x.0.42 x 0.06) + (2 x 0.010) = 12.8 m
No. of bent-up bar = 51.1/ .38 = 134.4 say 135 no.
3. Distribution bar 8 mm ^ @ 270 mm c/c
Length of straight bar = 51.1 - 2 end cover + 2 hooks = 51.1 - 0.08 + ( 18 x 0.008) = 51.2 m
No. of bars = 12.6/ .27 = 1260 / 270
= 46.6 say 47 no.
Sr. no.
Description
Shape
Length
No.
Total length (m)
Wt./m length
Total wt. (kg)
1.
Main bar 10 mm 4> @ 190
mm c/c

12.7
1 3 6
1727.2
0.62
1107.1
2.
Main bent- up bar10 mm
4> @ 190 c/c

12.8
1 3 5
1728
0.62
1072.1
3.
Distribution bars 8 mm 4> @ 270 mm c/c

51.2
47
358.4
0.39
139.8
Total 2318 kg = 23.18 quintal


BAR BENDING SCHEDULE FOR LINTEL

Main straight bar 8 mm | Anchor bar 8 mm | Stirrups 6 mm | @ 150 mm c/c
1.  Main straight bar of 8 mm |
No. of bars = 2
Length of bar = L + bearing - end cover
= 1.2 + 0.20 - 0.08 = 0.92 m
= 92 cm
Total length of bar = L + 2 hooks
= 0.92 + (18 x 0.082) = 1.06 m = 106 cm So total length of main bar 8 mm | = 1.14 m each
2.  Anchor bar 8 mm |
No. of bars = 2
Length of bar L= 0.92 m
Total length of bar = 106 cm
3.  Stirrups 6 mm | @ 150 c/c
No. of stirrups at 5 cm c/c at the end = 2 no.
No. of stirrups at 8 cm in b/w = 92 - 10 ^ 8 = 8.25 say 9
Total no. of stirrups = 2+9 = 11 no.
Length of one stirrups = 2(22+90) + 30 extra

= 72 cm = 0.72 m Total length of 11 no. stirrups 6 mm ^ = 0.72 each
Sr. no.
Description
Shape
Length
No.
Total length (m)
Wt./m length
Total wt. (kg)
1.
Main st. bar 8 mm ^

1.06
2
2.12
0.4
0.85
2.
Anchor bar 8 mm ^

1.06
2
2.12
0.4
0.85
3.
Stirrups 6 mm ^

0.72
11
7.92
0.4
3.2
Total 4.9 kg


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