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Mix Design Calculations for conventional concrete

Mix Design Calculations for conventional concrete
Stipulations for proportioning:
Grade of designation                                          : M35
Type of cement                                                   : OPC 53 Grade
Maximum normal size of aggregate                   : 20 mm
Minimum cement content                                   : 340 kg/m3
Maximum water cement ratio                             : 0.4
Exposure conditions (IS: 456-2000, pg no.18)   : Severe
Workability (IS: 456-2000, pg no.17)                : Medium
Degree of supervision                                         : Good
Maximum cement content                                  : 400-500 kg/ m3(Assumption)
Test data for material:
Cement used                                                       : OPC 53 Grade
Specific Gravity of cement                                 : 3.15
Specific Gravity of coarse aggregate                  : 2.74
Fine Aggregate                                                    : 2.62
Water Absorption                                                : 0.5 -1%
Target strength for mix proportioning:
                                      Fck’                = fck + 1.65S
                       Target Strength       = 35 + 1.65*5
                                                       = 43.25 N/ mm2

Selection of Water cement ratio:
Maximum Water cement ratio: 0.45
Based on Experience adopt water cement ratio as 0.40
                          0.40<0.45(Hence ok)
Maximum water content               = 186 litre
                                                       = 186 + 6/100 *186
                                                       = 197 litre (Every 25 mm increase, add to 3%)
Super Plasticizer is used, the water can be reduced upto 20%
                                                      = 197 * 20/200 + 197
                                                      = 157.6 litre
Calculation of cement content :
 Water cement Ratio                     = 0.40
Cement Content                            = 157.6/ 0.40
                                                      = 394 kg /m3
Proportion of volume of Coarse aggregate and fine aggregate:
From Table no.3, Coarse aggregate corresponding to 20mm size aggregate and fine aggregate  ( zone-II) for present case water cement ratio   = 0.40
Therefore increase or decrease water cement ratio             = 0.1
Corrected proportion of volume of coarse aggregate for water cement ratio 0.4=0.664
Volume of Coarse aggregate                                               = 0.664* 0.9
                                                                                             = 0.5976
Volume of Coarse aggregate                                               = 1-0.5976
                                                                                             = 0.4024
MIX CALCULATIONS
a)Volume of concrete       = 1m3
b)Volume of cement         = (Mass of cement) / (specific Gravity of cement)*(1/1000)
                                          = 394 / (3.15*(1/1000))
                                          = 0.125 m3
c)Volume of water           = (Mass of water) /(specific Gravity of cement)*(1/1000)
                                          = (157.6)/ (1)*(1/1000)
                                          = 0.158 m3
d)Volume of chemical admixture (super plasticizer) @ 2% by mass of cementitious material
       = (Mass of chemical admixture)/( specific Gravity of      cement)*(1/1000)
       = (7.88/1.145) * (1/1000)
       = 0.00688
e)Volume all in aggregate = ( a-(b + c + d))
                                           = 1-(0.125+0.1576+0.0068)
                                           = 0.7105 m3
f)Mass of coarse aggregate  = e*vol. Of coarse aggregate * sp.gravity of CA*1000
                                             = 0.7105*0.5976*2.74*1000
                                             =1163.38 kg
g)Mass of fine aggregate     = e* vol. Of sand * sp.gravity of FA*1000
                                             = 0.7105*0.4024*2.62*1000
                                             = 749.07 kg


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I am Thomas Britto here to share my experiences in the civil engineering field to all my readers.Today many students are struggling to buy books at high prices. So I decided to start a blog and share my experience and knowledge with all my readers.


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